3f(2)-5=-2(x^2+2x+1)+3

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Solution for 3f(2)-5=-2(x^2+2x+1)+3 equation: 


Simplifying
3f(2) + -5 = -2(x2 + 2x + 1) + 3

Reorder the terms for easier multiplication:
3 * 2f + -5 = -2(x2 + 2x + 1) + 3

Multiply 3 * 2
6f + -5 = -2(x2 + 2x + 1) + 3

Reorder the terms:
-5 + 6f = -2(x2 + 2x + 1) + 3

Reorder the terms:
-5 + 6f = -2(1 + 2x + x2) + 3
-5 + 6f = (1 * -2 + 2x * -2 + x2 * -2) + 3
-5 + 6f = (-2 + -4x + -2x2) + 3

Reorder the terms:
-5 + 6f = -2 + 3 + -4x + -2x2

Combine like terms: -2 + 3 = 1
-5 + 6f = 1 + -4x + -2x2

Solving
-5 + 6f = 1 + -4x + -2x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 6f = 1 + -4x + 5 + -2x2

Combine like terms: -5 + 5 = 0
0 + 6f = 1 + -4x + 5 + -2x2
6f = 1 + -4x + 5 + -2x2

Reorder the terms:
6f = 1 + 5 + -4x + -2x2

Combine like terms: 1 + 5 = 6
6f = 6 + -4x + -2x2

Divide each side by '6'.
f = 1 + -0.6666666667x + -0.3333333333x2

Simplifying
f = 1 + -0.6666666667x + -0.3333333333x2

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